If it's not what You are looking for type in the equation solver your own equation and let us solve it.
36=64-x^2
We move all terms to the left:
36-(64-x^2)=0
We get rid of parentheses
x^2-64+36=0
We add all the numbers together, and all the variables
x^2-28=0
a = 1; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·1·(-28)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*1}=\frac{0-4\sqrt{7}}{2} =-\frac{4\sqrt{7}}{2} =-2\sqrt{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*1}=\frac{0+4\sqrt{7}}{2} =\frac{4\sqrt{7}}{2} =2\sqrt{7} $
| 3x+5°=180° | | F(x)=2|x+4| | | Y=4x-7/2 | | 5.514+9.2r=158.234 | | 7n=21/7 | | -8/9a=16 | | -10.5+m/11.57=-2.78 | | 2019^x+2020^x=2021^x | | F(x)=2(4x-3)² | | ⁴√16(√16)z-3/2z-15z+81=0 | | ³√125d-4/3d-21=12d | | 90=2y-15y+12 | | x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)+(x+7)+(x+8)+(x+9)+(x+10)+(x+11)+(x+12)+(x+13)+(x+14)+(x+15)+(x+16)+(x+17)+(x+18)+(x+19)+(x+20)=1000 | | (d+7)(d+4)=-2 | | 17p-7=6p^2 | | x²–49=0 | | (12•2)2x=60 | | x6+5=41 | | y÷-3+4=11 | | 7^x=45 | | 14x+30=13.5x+36 | | 14x+30=5x+36 | | 3b+14=-6+2b | | 3b+14=–6+2b | | {2}{3}x-12=18 | | 100/12-x=8 | | 1-1k-3=2 | | 7(x+14)=49 | | 42-5x=10x-36 | | 2x=-1-1=x-3-(-5+x) | | x+x+x+x–8=12 | | 9y+4.8=17 |